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Jan 2, 2023 at 22:19 comment added KP Hart Or: every ultrafilter contains, for every $n$, a set of density $\frac1n$: just Take $X(n,i)=\{k:k\equiv i\pmod n\}$ for $n\in\mathbb{N}$, and $i\in\{1,2,\ldots,n\}$. If $u$ is an ultrafilter then for every $n$ there is an $i$ such that $X(n,i)\in u$.
Nov 25, 2022 at 21:28 vote accept Dominic van der Zypen
Nov 24, 2022 at 17:52 history edited Joel David Hamkins CC BY-SA 4.0
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Nov 24, 2022 at 17:40 history edited Joel David Hamkins CC BY-SA 4.0
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Nov 24, 2022 at 17:34 history edited Joel David Hamkins CC BY-SA 4.0
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Nov 24, 2022 at 17:24 history answered Joel David Hamkins CC BY-SA 4.0