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Nov 20, 2022 at 9:19 history edited Sam Nead CC BY-SA 4.0
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Nov 20, 2022 at 8:11 comment added Moishe Kohan I guess I did not make myself very clear (my bad): What you proved is that your surface does not admit a locally isometric map to any compact hyperbolic surface. (With a bit more work, one also sees that this surface also does not admit any $\pi_1$-injective holomorphic map to any compact hyperbolic Riemann surface.) But this does not answer the OP which is about nonconstant holomorphic maps and these are not even local diffeomorphisms.
Nov 19, 2022 at 20:18 comment added Moishe Kohan A nonconstant holomorphic map need not be a covering.
Nov 19, 2022 at 20:06 history answered Sam Nead CC BY-SA 4.0