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Nov 12, 2022 at 23:01 comment added Christian Remling @EmilJeřábek: This is actually a nicer way of stating the condition.
Nov 12, 2022 at 22:47 comment added Emil Jeřábek @ChristianRemling Or equivalently, $\operatorname{int}\overline A\subseteq A\subseteq\overline{\operatorname{int}A}$.
Nov 12, 2022 at 22:10 comment added Gro-Tsen Along similar lines: a set is regular open iff its characteristic function is normal lower semicontinuous (meaning that $f(x) = \operatorname{lim.sup}_{y\to x} \operatorname{lim.inf}_{z\to y} f(z)$).
Nov 12, 2022 at 21:48 comment added Christian Remling $\chi_A$ quasi-continuous is (obviously) equivalent to both $A$ and $A^c$ having dense open subsets, and I'm not sure if there is a better way of saying this.
Nov 12, 2022 at 20:30 comment added Joel David Hamkins Why do you need both $\epsilon$ and $\delta$? Isn't it equivalent to take $\epsilon=\delta$? Replace each with the minimum...
Nov 12, 2022 at 20:23 history asked Sam Sanders CC BY-SA 4.0