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Nov 22, 2022 at 15:24 vote accept Akira
Nov 20, 2022 at 17:02 comment added Nik Weaver Yeah, looks fine. Good for you.
Nov 20, 2022 at 12:02 comment added Akira @NikWeaver Could you have a check on my below answer? It seems the proof depends an a special property (the Lemma) of the canonical isometric isomorphism.
Nov 20, 2022 at 12:00 answer added Akira timeline score: 1
Nov 15, 2022 at 4:37 comment added Nik Weaver Well, a quick way to do it is by applying Theorem 1 to $\Omega_1 \cup \ldots \cup \Omega_n$. The isometry it gives is just the isometry for each $k$, patched together.
Nov 14, 2022 at 22:56 comment added Akira @NikWeaver I'm sorry if I'm bothering you. Could you please have a look at my update and elaborate on how to finish the reverse inequality? I would like to learn it very much...
Nov 14, 2022 at 11:59 comment added Akira @JochenWengenroth I have formalized your idea here. It's elegant!
Nov 13, 2022 at 22:15 comment added Akira @JochenWengenroth It seems I got your idea. I will try to formalize it. On the other hand, I'm curious if my failed approach can be fixed...
Nov 13, 2022 at 21:30 comment added Akira @NikWeaver I have tried but fail to prove the existence of such $f$ that $$\left [ \sum_{m=1}^n \frac{|H_m (f_m)|}{\|f_m\|_{L_{p}(\mu_m, X)}} \right ]^q \le \left [ \frac{|H (f)|}{\|f\|_{L_{p}(\mu, X)}} \right ]^q$$? Could you elaborate more?
Nov 13, 2022 at 21:30 history edited Akira CC BY-SA 4.0
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Nov 13, 2022 at 14:38 comment added Jochen Wengenroth Did you try the simple fact that every $\sigma$-finite measure $\mu$ is of the form $\mu= \varphi\cdot \nu$ for a finite measure $\nu$ and a density $\varphi:\Omega \to (0,\infty)$?
Nov 13, 2022 at 13:57 comment added Nik Weaver Now show that $\|L\|^q \geq \sum_1^n \|L_k\|^q$ for any $n$.
Nov 13, 2022 at 13:40 comment added Akira @NikWeaver I'm able to prove that $\|L\|^q \le \sum \|L_n\|^q$. However, I failed to prove the reverse inequality. Could you have a check on my update?
Nov 13, 2022 at 12:27 history edited Akira CC BY-SA 4.0
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Nov 12, 2022 at 17:30 comment added Nik Weaver Hint: check that $\|L\|^q = \sum \|L_n\|^q$.
Nov 12, 2022 at 17:26 history edited Akira CC BY-SA 4.0
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Nov 12, 2022 at 17:20 history asked Akira CC BY-SA 4.0