Timeline for Finding the determinant of a matrix with LU composition
Current License: CC BY-SA 2.5
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 25, 2010 at 1:12 | vote | accept | Arnfred | ||
| Oct 25, 2010 at 1:12 | comment | added | Arnfred | Damn, well that would explain my confusion. My reference L and U are from a tutorial explaining how to do the factorization, so it didn't even occur to me to check them. Thanks a lot! | |
| Oct 25, 2010 at 0:57 | comment | added | J. M. isn't a mathematician | Here, one can straightforwardly multiply together the diagonal elements of $\mathbf{U}$ since the permutation matrix output is the identity permutation. If the permutation was not the identity, one should multiply the product of the diagonals with -1 if the number of swaps was odd, and 1 otherwise for the determinant. | |
| Oct 24, 2010 at 22:09 | history | answered | Mike Spivey | CC BY-SA 2.5 |