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Nov 11, 2022 at 16:09 comment added Piotr Achinger In fact Stacks Project, Lemma 06DM implies that "geometrically unibranch" is equivalent to "etale locally irreducible".
Nov 11, 2022 at 16:05 comment added Piotr Achinger See Hartshorne "Algebraic Geometry" Chapter III, Exercise 10.6
Nov 11, 2022 at 16:01 comment added ofiz Are you saying that there is an étale morphism $f : X \rightarrow Y$, where $Y$ is the node, such that $X$ connected, yet reducible? If so, is it trivial to construct it? Thank you
Nov 11, 2022 at 15:30 comment added Piotr Achinger The node is not etale locally irreducible. So the answer to your question is negative outside the geometrically unibranch case.
Nov 11, 2022 at 15:26 history asked ofiz CC BY-SA 4.0