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Oct 24, 2010 at 18:20 vote accept TonyS
Oct 24, 2010 at 17:56 comment added Angelo I am pretty sure that being torsion-free is not required; but you are right, finiteness probably is needed in the argument.
Oct 24, 2010 at 17:18 comment added TonyS This looks good. But then it seems to me, that this is in fact true for all $R$-modules $M$ and $N$. Or do we need the finiteness assumptions? Because i think, if $A\rightarrow B$ is the splitting extension, then $Hom_R(M,N)\otimes_A B \cong Hom_{R\otimes_A B}(M\otimes_A B,N\otimes_A B)$ isn't true for all $R$-modules.
Oct 24, 2010 at 16:07 history answered Angelo CC BY-SA 2.5