Timeline for Assigning values to divergent oscillating integrals
Current License: CC BY-SA 4.0
5 events
when toggle format | what | by | license | comment | |
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Nov 10, 2022 at 7:34 | vote | accept | Caleb Briggs | ||
Nov 6, 2022 at 8:48 | comment | added | order | This is indeed the case—the reason is that the primitive of cosine vanishes at $0$ and has (distributional) limit $0$ at infinity. I suggest you take a look at the reference I suggested where such simple examples are computed explicitly. | |
Nov 4, 2022 at 22:28 | comment | added | Caleb Briggs | Is there a form of the theory in which $\int_0^\infty \cos(x) = 0$? In all of the contexts for which I have looked at, the integral should be zero (for instance, Cesaro means, shifting, and smoothing all give zero). | |
S Nov 4, 2022 at 8:03 | review | First answers | |||
Nov 4, 2022 at 8:08 | |||||
S Nov 4, 2022 at 8:03 | history | answered | order | CC BY-SA 4.0 |