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Nov 4, 2022 at 7:40 answer added dohmatob timeline score: 0
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Nov 3, 2022 at 23:30 answer added Thomas Kojar timeline score: 2
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Nov 2, 2022 at 0:01 comment added dohmatob Also note that my question is sufficient conditions on $X$ to ensure that $L(S_p^n,t) \to 0$ in the limit $t\to 0^+$. So passing via Hardy-Littlewood, in the ideal case what would you expect such a condition on the density of $f$ to look like ?
Nov 1, 2022 at 23:46 comment added dohmatob @ThomasKojar Thanks for bringing up Littlewood max function. However, I don't quite see how one would use this to argue about individual $u$'s that occur in the definition $L(X'w,t):=\sup_{u \in \mathbb R}\mathbb P(|X'w-u| \le t)$. Clear details would be appreciated.
Nov 1, 2022 at 22:17 comment added Thomas Kojar how about using the maximal operator estimate (en.wikipedia.org/wiki/Hardy%E2%80%93Littlewood_maximal_function) for the density f of X: $$|\{u \ : \ Proba(|X-u|<t) >t \alpha\}| \leq |\{u \ : \ (Mf)(u) > \alpha\}| \leq \frac{c}{\alpha}\int_{\mathbf{R}^n} |f|$$ to get that in in the tail ends: |u|>R for some fixed R, we have P(|X-u|<t) <t and in |u|<R we might have P(|X-u|<t) >t but because the region is bounded, we can try to apply extreme value theorem?
Nov 1, 2022 at 13:25 history edited dohmatob CC BY-SA 4.0
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Nov 1, 2022 at 11:52 comment added dohmatob Any reason why this question has been downvoted without comment ?
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Nov 1, 2022 at 8:19 history asked dohmatob CC BY-SA 4.0