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Nov 26, 2022 at 8:42 comment added Sam Nead As I noted below, “half” of the isometries of the hyperbolic plane are orientation reversing. However, Mobius transformations are orientation preserving. So the lemma you cite is missing a hypothesis (or a conclusion). If you add “negative complex conjugation” to the group $\mathrm{PSL}$ then you will get all isometries.
Nov 26, 2022 at 5:39 vote accept gaoqiang
Nov 20, 2023 at 12:03
Nov 26, 2022 at 5:39 vote accept gaoqiang
Nov 26, 2022 at 5:39
Nov 26, 2022 at 5:38 history edited gaoqiang CC BY-SA 4.0
added 773 characters in body
Nov 25, 2022 at 16:12 comment added Ryan Budney If your "domain" isn't connected, then the answer would be no.
Nov 25, 2022 at 5:30 comment added Moishe Kohan You should edit the question and explain what do you mean by an "isometry" (so that the word "injective" is not redundant and also make it clear if your definition includes "orientation-preserving") and does the word "domain" mean "open and connected" (as customary in complex analysis).
Nov 25, 2022 at 0:53 answer added Gerald Edgar timeline score: 3
Nov 25, 2022 at 0:26 comment added LSpice Isn't "injective" redundant in "injective and an isometry"?
Nov 25, 2022 at 0:26 history edited LSpice CC BY-SA 4.0
Typo
Nov 24, 2022 at 19:05 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Oct 25, 2022 at 18:39 answer added Sam Nead timeline score: 3
Oct 25, 2022 at 16:10 history asked gaoqiang CC BY-SA 4.0