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Post Closed as "Not suitable for this site" by Steven Landsburg, Yemon Choi, D.-C. Cisinski, Roland Bacher, Neil Strickland
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At the end of the proof of lemma 10, lemma 8 is cited. In order to use it and finish the contradiction, we need to show $n$ is not a multiple of $3.$ However, I don't see any contradiction in having $n \equiv \pm 2 \mod 8$ and $n \equiv 0 \mod 3.$ I also asked on MSE but not even a halfpenny of thoughts were given.

Proof: https://sci-hub.se/https://doi.org/10.1080/00029890.1990.11995558Anglin - The square pyramid puzzle.

At the end of the proof of lemma 10, lemma 8 is cited. In order to use it and finish the contradiction, we need to show $n$ is not a multiple of $3.$ However, I don't see any contradiction in having $n \equiv \pm 2 \mod 8$ and $n \equiv 0 \mod 3.$ I also asked on MSE but not even a halfpenny of thoughts were given.

Proof: https://sci-hub.se/https://doi.org/10.1080/00029890.1990.11995558

At the end of the proof of lemma 10, lemma 8 is cited. In order to use it and finish the contradiction, we need to show $n$ is not a multiple of $3.$ However, I don't see any contradiction in having $n \equiv \pm 2 \mod 8$ and $n \equiv 0 \mod 3.$ I also asked on MSE but not even a halfpenny of thoughts were given.

Proof: Anglin - The square pyramid puzzle.

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Elementary proof of cannonball problem: why can't $n$ be a multiple of $3$?

At the end of the proof of lemma 10, lemma 8 is cited. In order to use it and finish the contradiction, we need to show $n$ is not a multiple of $3.$ However, I don't see any contradiction in having $n \equiv \pm 2 \mod 8$ and $n \equiv 0 \mod 3.$ I also asked on MSE but not even a halfpenny of thoughts were given.

Proof: https://sci-hub.se/https://doi.org/10.1080/00029890.1990.11995558