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Oct 21, 2022 at 22:22 comment added Peter Taylor A direct approach along these lines would be to target $(x^2 + y)[1 \le y \le 2x]$ as $(x^2 + y)[1 \le y,z][y+z = 2x + 1]$ giving $$E(x,y,z) = (x^2 + y)(1 - (2x-y-z+1)^2)$$ I'm not sure that it makes it easier to eliminate the third variable, though.
Oct 21, 2022 at 21:48 comment added Peter Taylor It should be noted that the almost-answer I proposed in comments evaluates to non-integers when $x+y$ is even, so removing the fractional component could cause new problems.
Oct 21, 2022 at 21:43 history answered Pace Nielsen CC BY-SA 4.0