Skip to main content
8 events
when toggle format what by license comment
Oct 24, 2022 at 11:13 vote accept Didier de Montblazon
Oct 19, 2022 at 20:27 history became hot network question
Oct 19, 2022 at 15:04 comment added Neil Strickland The ring $K[x]/x^{n+1}$ is a Frobenius algebra, with the coproduct sending $x^i$ to $\sum_{j+k=n+i}x^j\otimes x^k$, but the subalgebra generated by $\{x^i:i>1\}$ is not.
Oct 19, 2022 at 14:45 answer added Dag Oskar Madsen timeline score: 7
Oct 19, 2022 at 13:53 answer added rschwieb timeline score: 4
Oct 19, 2022 at 13:35 review Close votes
Oct 27, 2022 at 3:05
Oct 19, 2022 at 12:34 comment added Benjamin Steinberg Matrix algebras over a field are Frobenius and every finite dimensional algebra embeds in a matrix algebra but many of them are not Frobenius
Oct 19, 2022 at 12:25 history asked Didier de Montblazon CC BY-SA 4.0