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Oct 19, 2022 at 12:29 vote accept Notamathematician
Oct 19, 2022 at 12:10 comment added domotorp I'm not so sure about that... Maybe you can pose it as another question and someone might answer it.
Oct 19, 2022 at 10:57 comment added Notamathematician Thank you for answer! Could you please also prove the recurrence: $a(n)=\frac{n(n-1)}{2}-b(n)$ for $n>0$ where $b(n)=b(\left\lfloor\frac{n}{2}\right\rfloor)+c(\left\lceil\frac{n}{2}\right\rceil-2)+\left\lfloor\frac{n}{2}\right\rfloor-1$ for $n>3$, otherwise $b(n)=0$ and where $c(n)$ is A181132.
Oct 19, 2022 at 6:51 history answered domotorp CC BY-SA 4.0