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Oct 19, 2022 at 11:03 comment added Carlo Beenakker there is no closed form solution; you could expand in powers of $a$ and obtain a series expansion...
Oct 18, 2022 at 21:05 comment added Dan Romik I tried it with Mathematica, it can do the first integral but gives up on your variant.
Oct 18, 2022 at 20:13 comment added username Well, there doesn't appear to be a formula in DMLF so your last chance is Watson..
Oct 18, 2022 at 17:58 history edited YCor
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S Oct 18, 2022 at 17:49 review First questions
Oct 18, 2022 at 19:31
S Oct 18, 2022 at 17:49 history asked Brian Isaac CC BY-SA 4.0