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Apr 5, 2023 at 14:06 answer added Saúl RM timeline score: 2
Apr 5, 2023 at 4:12 comment added Peter O. @Saúl RM : You should post your comment as an answer to keep this site from seeing this question as unanswered.
Oct 15, 2022 at 6:40 comment added Jack Okay, got it, thanks.
Oct 15, 2022 at 2:23 comment added Saúl RM The problem of which functions $f:[0,1]\to\mathbb{R}$ can be approximated by polynomials with non negative coefficients has already been studied: as theorem 2 of this paper states, a continuous function $f:[0,1]\to\mathbb{R}$ is a pointwise limit of polynomials with non negative coefficients iff $f(x)=\sum_{n=0}^\infty a_nx^n$ for some non negative sequence $a_n$ such that $\sum a_n<\infty$.
Oct 14, 2022 at 20:05 comment added Qiaochu Yuan As mathworker21 alludes to, this is impossible for, say, $f(x) = 4x - x^2$ because a uniform limit of convex functions is convex.
Oct 14, 2022 at 19:52 comment added mathworker21 what if $f$ is concave?
Oct 14, 2022 at 19:42 history edited Jack CC BY-SA 4.0
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Oct 14, 2022 at 19:38 history edited Jack CC BY-SA 4.0
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S Oct 14, 2022 at 19:30 review First questions
Oct 15, 2022 at 7:51
S Oct 14, 2022 at 19:30 history asked Jack CC BY-SA 4.0