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Oct 16, 2022 at 6:34 history edited Guoqing CC BY-SA 4.0
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Oct 16, 2022 at 5:23 vote accept Guoqing
Oct 14, 2022 at 10:48 comment added Carlo Beenakker I worked out the derivation in the answer box, but do note that the formula you wrote down for $G_{11}(z)$ neglects higher order terms in $z$ in the denominator.
Oct 14, 2022 at 10:47 answer added Carlo Beenakker timeline score: 3
Oct 13, 2022 at 0:52 comment added Guoqing @CarloBeenakker. It's in a paper, actually. And the result only hold for the large $N\to\infty$. See link
Oct 12, 2022 at 16:36 comment added Carlo Beenakker which text book? is this supposed to hold for any $N$?
Oct 12, 2022 at 14:56 history edited YCor
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Oct 12, 2022 at 14:44 history asked Guoqing CC BY-SA 4.0