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Timeline for Zeros of inverse of dilogarithm

Current License: CC BY-SA 4.0

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Oct 12, 2022 at 10:25 comment added Tom Goodwillie @DrorSpeiser : If it's true then I think you can find it in arxiv.org/abs/alg-geom/9202022 (section 2, Monodromy).
Oct 12, 2022 at 7:51 comment added Dror Speiser @HenriCohen : nah, try increasing truncation degree and you'll see that zero disappear
Oct 12, 2022 at 6:49 comment added Dror Speiser @TomGoodwillie : that's what I would hope for. Can this be proved?
Oct 12, 2022 at 6:47 comment added Dror Speiser @Conrad : the compositional inverse can be defined from the power series, and I don't think it's a multivalued function. This is similar to log being multivalued but exp is not.
Oct 12, 2022 at 1:04 comment added Tom Goodwillie That is, the numbers that arise as values of the multi-valued function $Li_2(x)$ at $x=0$ are precisely the numbewrs $4\pi^2k$, $k\in\mathbb Z$.
Oct 12, 2022 at 1:03 comment added Tom Goodwillie I think that the answer is: the integer multiples of $4\pi^2$.
Oct 12, 2022 at 0:03 comment added Conrad what do you mean by compositional inverse and also by $Li_2$ (in the sense that $Li_2$ is a multivalued function with branch points at $1, \infty$ so do you think of $Li_2$ as defined on say the complex plane minus $[1,\infty]$ as the "main branch" or something else?
Oct 11, 2022 at 20:47 comment added Martin Rubey I have no idea whether it helps, but it is at least fun - the compositional inverse satisfies a relatively nice differential equation: $x^{3} f'\left(x\right)^{3} + {\left(x + 1\right)} f\left(x\right)^{3} + 3 \, x f\left(x\right)^{2} f'\left(x\right) - {\left(x^{2} - {\left(x^{3} + 3 \, x^{2}\right)} f\left(x\right)\right)} f'\left(x\right)^{2} - f\left(x\right)^{2} - {\left(x^{3} f\left(x\right)^{2} - x^{2} f\left(x\right)\right)} f''\left(x\right) = 0$
Oct 11, 2022 at 20:24 history edited Ira Gessel CC BY-SA 4.0
deleted 1 character in body
Oct 11, 2022 at 19:57 history asked Dror Speiser CC BY-SA 4.0