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Oct 11, 2022 at 17:44 comment added THC Doesn't the case $n = 2$ (for $\mathbf{PGL}_2(D)$) directly follows from the case of $\mathbf{PSL}_2(D)$ plus the fact that the latter is generically a characteristic subgroup of $\mathbf{PGL}_2(D)$ ? (An isomorphism between the $\mathbf{PGL}_2$s induces an isomorphism between the $\mathbf{PSL}_2$s.)
Oct 11, 2022 at 17:30 history edited Denis T CC BY-SA 4.0
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Oct 11, 2022 at 17:23 history edited Denis T CC BY-SA 4.0
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Oct 11, 2022 at 17:06 history edited Denis T CC BY-SA 4.0
expanded and fixed factual errors
Oct 11, 2022 at 14:52 comment added Denis T @THC ...Well, I was a bit too eager to include $n = 2$ case without some nuances; I'll edit the answer to promote it from containing almost true statements to being true.
Oct 11, 2022 at 14:05 comment added THC In O'Meara's paper, the author seems to be assuming that $n \geq 5$ ? Are the cases $n = 2, 3, 4$ also covered (somewhere) ?
Oct 11, 2022 at 13:14 history edited Denis T CC BY-SA 4.0
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Oct 11, 2022 at 12:32 vote accept THC
Oct 11, 2022 at 12:11 history edited Denis T CC BY-SA 4.0
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Oct 11, 2022 at 12:01 history answered Denis T CC BY-SA 4.0