Timeline for For most directions does the supporting hyperplane meeting a bounded convex set meet it in one point?
Current License: CC BY-SA 4.0
6 events
when toggle format | what | by | license | comment | |
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Oct 22, 2022 at 2:58 | comment | added | Piotr Hajlasz | @DeaneYang I posted an answer which gives a much stronger result. | |
Oct 10, 2022 at 23:09 | comment | added | Deane Yang | Ah, yes. I see. | |
Oct 10, 2022 at 19:46 | comment | added | Alexander Pruss | If $C$ is not bounded, $H_v$ might not be defined. | |
Oct 10, 2022 at 19:24 | comment | added | Deane Yang | The assumption that $C$ is bounded is not needed. Even if $C$ is unbounded, its boundary is locally Lipschitz and therefore by Rademacher's theorem, is locally differentiable almost everywhere. | |
Oct 10, 2022 at 19:06 | vote | accept | Alexander Pruss | ||
Oct 10, 2022 at 18:03 | history | answered | alesia | CC BY-SA 4.0 |