Timeline for Analytic value of $\alpha := \sup_{(x,y) \in C} ax+by$, where $C := \{(x,y) \in \mathbb R^2 \mid x^2 + y^2 \le 1,\,x^2 + c y^2 \le R^2\}$
Current License: CC BY-SA 4.0
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Oct 9, 2022 at 13:04 | history | edited | RobPratt |
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Oct 9, 2022 at 10:40 | comment | added | dohmatob | @RiverLi For some reason the change wasn't saved. Fixed. | |
Oct 9, 2022 at 10:39 | history | edited | dohmatob | CC BY-SA 4.0 |
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Oct 9, 2022 at 9:58 | comment | added | River Li | You forgot to change $\alpha = |a|\min(1,R/\sqrt c)$ to $\alpha = |b|\min(1,R/\sqrt c)$. | |
Oct 9, 2022 at 9:19 | comment | added | dohmatob | @RiverLi Fixed. Thanks! | |
Oct 8, 2022 at 15:31 | vote | accept | dohmatob | ||
Oct 8, 2022 at 13:51 | history | edited | dohmatob | CC BY-SA 4.0 |
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Oct 8, 2022 at 12:37 | answer | added | River Li | timeline score: 2 | |
Oct 8, 2022 at 12:27 | comment | added | River Li | Some typos: First line, it should be $(x, y) \in \mathbb{R}^2$. "If $a=0$ ...", it should be $\alpha = |b| \min(1, R/\sqrt c)$. | |
Oct 8, 2022 at 10:36 | history | edited | dohmatob | CC BY-SA 4.0 |
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Oct 8, 2022 at 9:24 | history | edited | dohmatob | CC BY-SA 4.0 |
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Oct 8, 2022 at 7:32 | history | edited | dohmatob | CC BY-SA 4.0 |
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Oct 8, 2022 at 7:25 | history | asked | dohmatob | CC BY-SA 4.0 |