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Oct 7, 2022 at 4:40 history edited YCor
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Oct 6, 2022 at 13:12 comment added Carlo Beenakker if I may assume that $A$ is Hermitian, the integral can be rewritten as $$\int \left(\sum_n y_n |U_{n1}|^2\right)\left(\sum_n z_n|U_{n1}|^2\right)^{-1}\,dU$$ for some set of coefficients $y_n,z_n$; there is no closed form answer; for large $d$ you could take independent normal distributions for the $U_{n1}$ elements, but that's about it.
S Oct 6, 2022 at 13:02 review First questions
Oct 6, 2022 at 13:13
S Oct 6, 2022 at 13:02 history asked N A McMahon CC BY-SA 4.0