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Oct 16, 2022 at 10:01 vote accept Michal Kotowski
Oct 3, 2022 at 15:36 history edited Joseph Van Name CC BY-SA 4.0
Did a calculation as a response to Peter Taylor's remarks
Oct 3, 2022 at 14:52 comment added Joseph Van Name @PeterTaylor. That is true. I will reword my answer to take that into consideration.
Oct 3, 2022 at 14:45 comment added Peter Taylor The characteristic polynomial is a determinant, so the matrix determinant lemma gives us $\chi(A + uv^T) = (1 + v^T (A - xI)^{-1} u) \chi(A)$. Should the last paragraph be interpreted as wanting a stronger result than this?
Oct 3, 2022 at 13:29 history answered Joseph Van Name CC BY-SA 4.0