Timeline for Inner products on super vector spaces
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Oct 3, 2022 at 13:39 | comment | added | Jonas | @ChrisSchommer-Pries I removed the choice of basis and the presentation of the trace in coordinates. I believe one should actually use a 'difference' of two scalar products on $V^0$ and $V^1$ to do this (then negative definite on $V^1$), but this seems arbitrary to me. | |
| Oct 3, 2022 at 13:36 | history | edited | Jonas | CC BY-SA 4.0 |
removed choice of basis in construction.
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| Oct 2, 2022 at 9:32 | comment | added | Jonas | No, you are right it should be a (non-super) symplectic basis of $V^1$. I will edit the answer, thanks. | |
| Sep 30, 2022 at 14:05 | comment | added | Chris Schommer-Pries | Perhaps I am confused. Doesn't your symmetry condition mean that the restriction of B to the odd part of V is a (non-super) anti-symmetric form? So a symplectic form if non-degenerate. Then it would not have the basis you claim, but a different one. | |
| Sep 30, 2022 at 13:14 | history | answered | Jonas | CC BY-SA 4.0 |