Timeline for Proof of lower bound on variance
Current License: CC BY-SA 4.0
7 events
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| Sep 30, 2022 at 6:34 | comment | added | Steve | The last two integrals simply converge to zero. I think that there is a lot of slack in the statement of the Lemma by not specifying $c_1$. For the term $2^{-1/\beta}$, I think any other constant $(1+\delta)$ instead of 2 would work as well where for arbitrarily small $c_1$, the $\delta$ also can be chosen smaller. The paper seems to side-step this precise weighing and simply takes $\delta=1$. | |
| Sep 29, 2022 at 19:44 | comment | added | n3rl | This was very helpful, thanks! I have one more question; in the last step, how do we know that the two integrals are small enough that the entire expression is $\geq 1/\{sqrt{2}}$? | |
| Sep 29, 2022 at 19:36 | vote | accept | n3rl | ||
| S Sep 28, 2022 at 21:35 | history | suggested | CommunityBot | CC BY-SA 4.0 |
a couple of small MathJax corrections
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| Sep 28, 2022 at 20:10 | review | Suggested edits | |||
| S Sep 28, 2022 at 21:35 | |||||
| Sep 28, 2022 at 18:05 | history | edited | Steve | CC BY-SA 4.0 |
added 6 characters in body
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| Sep 28, 2022 at 15:00 | history | answered | Steve | CC BY-SA 4.0 |