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when toggle format what by license comment
Sep 26, 2022 at 16:39 comment added user124784 Embarrassingly simple! It seems I was overthinking things. Thanks.
Sep 26, 2022 at 16:37 history edited Nawaf Bou-Rabee CC BY-SA 4.0
corrected a typo in the definition of the linear approx
Sep 26, 2022 at 16:35 comment added Nawaf Bou-Rabee It seems you are right, since $| \hat{f}(x) - f(x)| = |\frac{d-x}{d} ( f(0) - f(x) ) + \frac{x}{d} (f(d) - f(x))| \le \frac{d- x}{d} x + \frac{x}{d} (d - x) = \frac{(d - x) x}{d/2} $ which seems to be largest when $x=d/2$ to obtain $C(d) = d/2$.
Sep 26, 2022 at 16:03 history asked user124784 CC BY-SA 4.0