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Sep 24, 2022 at 18:02 vote accept Misha Verbitsky
Sep 22, 2022 at 21:43 answer added Sam Nead timeline score: 6
Sep 22, 2022 at 20:03 history edited Misha Verbitsky CC BY-SA 4.0
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Sep 22, 2022 at 20:02 comment added Misha Verbitsky Thanks! Yes, I was asking about an ifinite order element. I will make a correction
Sep 22, 2022 at 19:40 comment added YCor Let $g$ be of infinite order, with arbitrary large roots $g_n$. Each $g_n$ commutes with $g$. But the centralizer of $g$ is finite-by-cyclic, i.e., surjects onto $\mathbf{Z}$ with finite kernel. Projecting, we get a contradiction.
Sep 22, 2022 at 19:38 comment added YCor Torsion elements are infinitely divisible. So you're asking about elements of infinite order.
Sep 22, 2022 at 19:33 history asked Misha Verbitsky CC BY-SA 4.0