Skip to main content
9 events
when toggle format what by license comment
Sep 22, 2022 at 18:47 history became hot network question
Sep 22, 2022 at 16:33 vote accept bernardorim
Sep 22, 2022 at 12:26 answer added David E Speyer timeline score: 8
Sep 22, 2022 at 12:15 history edited bernardorim CC BY-SA 4.0
edited body
Sep 22, 2022 at 12:12 comment added Chris H The usual identification of symmetric powers of the line with projective space goes via encoding polynomials as their roots, which seems to mess with the point counting equalities you gave. Someone more knowledgeable can hopefully see what’s going on here.
Sep 22, 2022 at 12:10 comment added bernardorim Of course, +2 instead of +1, that was a typo, thanks! And I also edited the notation for over $\mathbb F_p$
Sep 22, 2022 at 12:08 history edited bernardorim CC BY-SA 4.0
edited body
Sep 22, 2022 at 11:03 comment added YCor The quotient map might not be surjective on $\mathbf{F}_p$-points. I didn't look carefully at this example, but for another action of a group of order $2$: the homomorphism $\mathrm{SL}_2\to\mathrm{PGL}_2$ is surjective, but not surjective on $F$-points when $F$ is a finite field of odd cardinal.
Sep 22, 2022 at 10:46 history asked bernardorim CC BY-SA 4.0