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Sep 22, 2022 at 15:59 comment added Denis T You can read a lot about presentation complexes from the book "Combinatorial group theory" by Lyndon&Schupp. (That text is a great starting point for anyone trying to learn low-dimensional topology from algebraic point of view!)
Sep 22, 2022 at 10:44 comment added Carl-Fredrik Nyberg Brodda @BenjaminSteinberg Ah, thanks! That's what I was missing.
Sep 22, 2022 at 10:23 comment added Benjamin Steinberg To get the Schur multiplier you need at least the 3-skeleton of a classifying space
Sep 22, 2022 at 9:46 review Close votes
Oct 17, 2022 at 3:04
Sep 22, 2022 at 9:29 comment added Fernando Muro The presentation complex has dimension at most 2 and the 2-dimensional homology of a 2-dimensional complex with coefficients in the integers is always free.
Sep 22, 2022 at 9:20 comment added Carl-Fredrik Nyberg Brodda Maybe I'm being silly, but isn't this just the Schur multiplier for $G$? In this case, the answer to 1 is no -- the Schur multiplier of $C_2 \times C_2$ is $C_2$ (as is the Schur multiplier for $S_n$ with $n>3$, I believe).
Sep 22, 2022 at 9:15 history edited gola vat CC BY-SA 4.0
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S Sep 22, 2022 at 9:07 review First questions
Sep 22, 2022 at 11:00
S Sep 22, 2022 at 9:07 history asked gola vat CC BY-SA 4.0