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Sep 23, 2022 at 2:41 vote accept José María Grau Ribas
Sep 22, 2022 at 17:51 comment added Pace Nielsen Alternatively, just replace $F$ with $2\mathbb{Z}$, and adjust things accordingly.
Sep 22, 2022 at 17:50 comment added Pace Nielsen @rschwieb Good point. If they don't want it unital, they can add a new variable $z$, commuting with $x$ and $y$, and take the nonunital subring generated by $x,y,z$. This ring won't be unital, since it is graded by degree. It won't be nilpotent since $z$ isn't nilpotent. We didn't add any new idempotents, so it is still indecomposable.
Sep 22, 2022 at 17:33 comment added rschwieb There's some ambiguity: the title asks for "not unitary" whereas the body says "not finite unital." This is a great answer for the body question, at least (which I guess is probably the intended one.)
Sep 21, 2022 at 22:46 history answered Pace Nielsen CC BY-SA 4.0