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Mar 21, 2023 at 3:33 comment added Iosif Pinelis @fedja : Oh, I see, thank you.
Mar 21, 2023 at 3:00 comment added fedja @IosifPinelis Nope, it isn't. What it is based upon is that for any vector $v$ the ratio $\|(I-x\otimes x)v\|/\|v\|$ is a random variable whose distribution does not depend on $v$ and those r.v. are independent at different steps. This is a rather clever trick that reduces everything to dimension 1.
Mar 21, 2023 at 1:23 comment added Iosif Pinelis It appears to me that this calculation is based on the assumption that some rotational symmetry implies that the norm of a product of matrices is the product of the norm. Is my impression mistaken?
Sep 19, 2022 at 18:19 vote accept Yaroslav Bulatov
Sep 19, 2022 at 17:55 history edited Anthony Quas CC BY-SA 4.0
added 14 characters in body
Sep 19, 2022 at 17:40 history answered Anthony Quas CC BY-SA 4.0