Timeline for Is there a $3$-commutative algebra?
Current License: CC BY-SA 4.0
17 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 5, 2022 at 18:05 | answer | added | Maarten Havinga | timeline score: 4 | |
| Oct 5, 2022 at 14:40 | answer | added | Vladimir Dotsenko | timeline score: 5 | |
| Sep 18, 2022 at 6:11 | comment | added | Denis Serre | @NoamD.Elkies Yes, I assume associative algebra. | |
| Sep 17, 2022 at 20:51 | comment | added | Noam D. Elkies | I guess that these algebras are implicitly assumed associative, else a product of 3 or more algebras is not well-defined; is that what you meant? | |
| Sep 17, 2022 at 19:27 | history | edited | Denis Serre | CC BY-SA 4.0 |
added 361 characters in body
|
| Sep 17, 2022 at 18:30 | answer | added | Vladimir Dotsenko | timeline score: 5 | |
| Sep 17, 2022 at 17:13 | comment | added | YCor | I believe the terminology is misleading and the failure of commutativity should not be assumed (so that 3-commutative defines a variety). So the real question is about non-commutative 3-commutative algebras. | |
| Sep 17, 2022 at 17:10 | history | edited | YCor |
edited tags
|
|
| Sep 17, 2022 at 16:59 | answer | added | Salvatore Siciliano | timeline score: 12 | |
| Sep 17, 2022 at 16:20 | answer | added | Denis T | timeline score: 9 | |
| Sep 17, 2022 at 16:19 | comment | added | LSpice | @DenisSerre, I am sorry, I misunderstood @user49822's remark. I have deleted my comment. | |
| Sep 17, 2022 at 15:37 | comment | added | Denis Serre | @LSpice I am not sure to understand. $M_n(k)$ is $(2n)$-commutative in the sense I gave : there exist $2n-1$ matrices $a_j$ such that $P_{2n-1}(a_1,\ldots,a_{2n-1})\ne0$. | |
| Sep 17, 2022 at 15:22 | history | edited | LSpice | CC BY-SA 4.0 |
Typos, and link to comment
|
| Sep 17, 2022 at 15:14 | history | edited | Denis Serre | CC BY-SA 4.0 |
added 238 characters in body
|
| Sep 17, 2022 at 15:12 | comment | added | Denis Serre | @user49822 Oh yes ! Thank you for the remark. | |
| Sep 17, 2022 at 14:22 | comment | added | user49822 | Assuming $A$ is unital, if $m=2k+1$ and you substitute $X_m=1$ then the identity becomes the identity of $m-1$-commutativity | |
| Sep 17, 2022 at 9:57 | history | asked | Denis Serre | CC BY-SA 4.0 |