Timeline for Do taut foliations leafwise branch covering S^2 yield foliations by circles?
Current License: CC BY-SA 4.0
6 events
when toggle format | what | by | license | comment | |
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Sep 16, 2022 at 22:33 | vote | accept | Audrey Rosevear | ||
Sep 16, 2022 at 18:45 | answer | added | Andy Putman | timeline score: 3 | |
Sep 16, 2022 at 7:21 | comment | added | Sam Nead | I think that you mean "coordinates where $f$ looks like $(x, y, z) \mapsto (x^2 - y^2, 2xy)$". In your version $f$ is not surjective near the origin. Also, I think that $D = \mathrm{ker} f$ should be $D = \mathrm{ker} \, d\!f$. | |
Sep 16, 2022 at 5:44 | comment | added | Audrey Rosevear | The leaves here are precisely the preimages of points under $f$, so they should be compact. | |
Sep 16, 2022 at 3:18 | comment | added | Andy Putman | I haven’t read that paper, so this might be totally misguided. But why are the leaves of the 1-dimensional distribution closed? All closed oriented 3-manifolds support 1-dimensional foliations (since their Euler characteristic is 0, you can find a nonvanishing vector field on them). | |
Sep 16, 2022 at 2:04 | history | asked | Audrey Rosevear | CC BY-SA 4.0 |