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Sep 12, 2022 at 2:04 history edited alesia CC BY-SA 4.0
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Sep 12, 2022 at 1:12 comment added David E Speyer Okay, I get it now. Interesting question.
Sep 11, 2022 at 19:26 comment added alesia @Ycor yes that's correct. Starting from two dimensions things seem to get more complicated
Sep 11, 2022 at 18:33 comment added YCor For $n=1$, is it correct that we obtain exactly all convex non-decreasing functions?
Sep 11, 2022 at 18:14 comment added alesia @YCor let's say pointwise convergence
Sep 11, 2022 at 18:06 history edited YCor CC BY-SA 4.0
made title more specific, added tag
Sep 11, 2022 at 18:04 comment added YCor You're assuming that the cone is closed with respect to which topology?
Sep 11, 2022 at 17:24 comment added alesia Also if you add two different functions of the form you described, you might get a function that is not of this form
Sep 11, 2022 at 17:22 comment added alesia The cone only contains coordinate functions, not their opposite (if you include opposite coordinate functions the cone includes all convex functions)
Sep 11, 2022 at 17:19 comment added David E Speyer It seems to me that every function in your cone is of the form $f(x_1, x_2, \ldots, x_n) = \max(a_1 x_1, a_2 x_2, \ldots, a_n x_n, -b_1 x_1, -b_2 x_2, \ldots, -b_n x_n, c)$ for some nonnegative constants $a_i$, $b_i$ and $c$. Can you give me an example of a function not of this form?
Sep 11, 2022 at 17:14 history asked alesia CC BY-SA 4.0