Timeline for On the equality $\{f\in C(X), f|_A=0\}+\{f\in C(X), f|_B=0\}=\{f\in C(X), f|_{A\cap B}=0\}$
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 13, 2022 at 9:02 | vote | accept | erz | ||
| Sep 12, 2022 at 21:20 | answer | added | KP Hart | timeline score: 7 | |
| Sep 10, 2022 at 13:42 | comment | added | R. van Dobben de Bruyn | The condition implies $X$ is normal, right? For if $A, B \subseteq X$ are disjoint closed subsets, then $J_{A \cap B} = C(X)$ so $1 = f+g$ for $f \in J_A$ and $g \in J_B$. Then $U = \{f < \tfrac{1}{2}\}$ and $V = \{g < \tfrac{1}{2}\}$ are disjoint open sets containing $A$ and $B$ respectively. | |
| Sep 10, 2022 at 9:25 | history | asked | erz | CC BY-SA 4.0 |