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Feb 19, 2023 at 20:55 comment added G. Panel Sorry, I didn't notice that you used: $E\cap\text{cone}(G')=\text{cone}(E\cap G')$, since $E$ and $G'$ contain the origin (hence the necessity to consider $\text{cone}(G')$ rather than $\text{Aff}(G')$).
Feb 19, 2023 at 20:48 vote accept G. Panel
Feb 19, 2023 at 20:42 comment added M. Winter @G.Panel I am not sure I understand. At this point in the proof $E,G'$ and $F$ are just linear subspaces resp. cones and this quotient is just linear algebra. Or am I overlooking something?
Sep 20, 2022 at 22:42 vote accept G. Panel
Feb 19, 2023 at 20:17
Sep 20, 2022 at 12:18 history edited M. Winter CC BY-SA 4.0
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Sep 20, 2022 at 11:19 history undeleted M. Winter
Sep 20, 2022 at 11:19 history edited M. Winter CC BY-SA 4.0
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Sep 17, 2022 at 22:26 history deleted M. Winter via Vote
Sep 12, 2022 at 20:25 history edited M. Winter CC BY-SA 4.0
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Sep 12, 2022 at 20:18 history edited M. Winter CC BY-SA 4.0
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Sep 9, 2022 at 22:33 history answered M. Winter CC BY-SA 4.0