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Sep 12, 2022 at 20:31 comment added Evgeny Shinder It seems a lot easier to use the whole derived pushforward (as a complex, not just the cohomology sheaves), so that if $\pi$ is a resolution and $\sigma$ is a smooth blow up, then $R(\pi\sigma)_*(\mathcal{O}) = R\pi_* R\sigma_*(\mathcal{O}) = R\pi_*(\mathcal{O})$. Using Weak factorization (in char. 0) this implies that the complex $R\pi_*(\mathcal{O})$ on a given singular variety $X$ is independent of the choice of the resolution $\pi$.
Sep 12, 2022 at 20:01 history edited Invariance
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Sep 12, 2022 at 12:49 history edited Invariance CC BY-SA 4.0
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Sep 11, 2022 at 1:12 answer added Karl Schwede timeline score: 2
Sep 9, 2022 at 16:05 history edited LSpice CC BY-SA 4.0
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Sep 9, 2022 at 15:45 history asked Invariance CC BY-SA 4.0