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Jan 17, 2023 at 13:25 vote accept M. Winter
Jan 17, 2023 at 13:26
Oct 12, 2022 at 22:55 comment added Francisco Santos Embedding in higher dimension does not give you additional 0/1 polytopes. If you have a $d$-polytope $P$ embedded in dimension $n$ for some $n>d$ there are always $n-d$ coordinates that you can forget, to obtain a projection of $P$ in $\mathbb R^d$ with the same combinatorial type. If $P$ was 0/1, the projection still is.
Oct 12, 2022 at 22:06 answer added Francisco Santos timeline score: 4
Sep 8, 2022 at 18:24 history became hot network question
Sep 8, 2022 at 15:13 answer added M. Winter timeline score: 6
Sep 8, 2022 at 13:04 comment added Sam Hopkins Doesn’t the number of combinatorial types of (say, simple) polytopes grow too fast for this (I mean, realizing every one as a 01-polytope) to be possible? EDIT: oh, I see, maybe this is what your comment about embedding in higher dimensions was meant to address.
Sep 8, 2022 at 10:22 history asked M. Winter CC BY-SA 4.0