Timeline for Arithmetic ampleness and scalings of the metric
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Sep 30, 2022 at 6:24 | comment | added | Robert Wilms | Right, for increasing $\alpha$ the norm of any section increases (by multiplication by $\alpha^{n/2}$). Thus, for some $\alpha$ and a fixed $n$ no section has sup-norm smaller 1. That's the intuition. My calculation just shows, that this happens uniformly for all $n$ if $\alpha\to\infty$. | |
| Sep 29, 2022 at 4:37 | comment | added | Bombyx mori | Do you think this can explained more plainly, for example by suggesting when $\alpha\rightarrow \infty$, this makes the number of sections with $\sup |s|<1$ smaller? While the question asked by OP is intuitively false by this naive heuristic, it seems the finite place contribution and ampleness is still important here. But can this be done via Minkowski theory, etc? Maybe a silly question... | |
| Sep 6, 2022 at 11:43 | vote | accept | manifold | ||
| Sep 2, 2022 at 20:49 | history | edited | Robert Wilms | CC BY-SA 4.0 |
added 5 characters in body
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| Sep 2, 2022 at 18:45 | history | answered | Robert Wilms | CC BY-SA 4.0 |