Timeline for Counting pieces when an object is cut n ways
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Sep 2, 2022 at 16:08 | comment | added | James Propp | Update: According to A000096 in the OEIS the answer is $n(n+3)/2$, which indeed takes the value $0$ at $n=0$. So maybe counting pieces by Euler measure works after all. | |
| Sep 2, 2022 at 3:26 | comment | added | James Propp | Oops! Gerry’s question prompted me to think harder, and I found a mistake in my analysis. So I don’t know what happens with the annulus. One might indeed get a quadratic function of $n$ for all $n$ sufficiently large, and plugging $n=0$ into this quadratic might indeed give 0 (as an Euler measure viewpoint would suggest) — I don’t know yet. | |
| Sep 2, 2022 at 0:55 | comment | added | Gerry Myerson | What does happen when slicing an annulus? | |
| Sep 1, 2022 at 20:19 | history | asked | James Propp | CC BY-SA 4.0 |