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Sep 6, 2022 at 20:24 vote accept Gro-Tsen
Aug 31, 2022 at 19:13 history became hot network question
Aug 31, 2022 at 12:50 comment added Oscar Lanzi The cube does not work here for $n=8$ either. Any prism is beaten by the antiprism obtained by twisting either basal face in-plane.
Aug 31, 2022 at 12:47 comment added Brian Hopkins It would be nice if the answers included the regular polytopes for the appropriate dimensions & number of points/vertices, but I see that the Thomson problem for 3-space and $n=8$ is the square antiprism, not the cube, and for $n=20$ it's not the dodecahedron.
Aug 31, 2022 at 11:31 history edited Gro-Tsen CC BY-SA 4.0
add a short PS about the "dual" problem
Aug 31, 2022 at 11:27 answer added Oscar Lanzi timeline score: 11
Aug 31, 2022 at 11:10 history asked Gro-Tsen CC BY-SA 4.0