Timeline for Explicit bounds on the difference between Bernstein polynomials
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 29, 2022 at 14:22 | comment | added | Peter O. | Indeed, $|B_{2n}(f) - B_n(f)| \le 2M/n$ whenever $|B_n(f) - f| \le M/n$ (Ditzian and May, A Saturation Result for Combinations of Bernstein Polynomials, Tôhoku Math. J. 28 [1976]), answering question 2. | |
| Aug 29, 2022 at 14:08 | comment | added | Peter O. | Thus, the answers to 1, 3, and 4 are "no". I thought I found a rate of $O(1/n^2)$, but I had written the numerical code for it wrong. | |
| Aug 29, 2022 at 14:07 | vote | accept | Peter O. | ||
| Aug 29, 2022 at 11:02 | history | answered | Giorgio Metafune | CC BY-SA 4.0 |