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Let $M$ be a smooth manifold and $f\in C^\infty(M)$. Let $S:=f^{-1}(\{c\})$ for some $c\in \operatorname{Im}(f)\subseteq\mathbb{R}$. When does exist a manifold $N$ with $\dim(N)<\dim(M)$ and a smooth immersion $\Phi :N\rightarrow M$ such that $\Phi (N)=S$? I guess that the interior of $S$ has to be empty.

Furthermore: when is $N$ unique up to dipheomorphism?

It's a well known result that if $c$ is a regular value then $S$ is a closed embedded submanifold. Sohypersurface, so, in that line of thinking, probably you need to put some conditions to $c$, but I don't know which ones.

Partial answers are also welcome.

Thanks in advance.

Let $M$ be a smooth manifold and $f\in C^\infty(M)$. Let $S:=f^{-1}(\{c\})$ for some $c\in \operatorname{Im}(f)\subseteq\mathbb{R}$. When does exist a manifold $N$ with $\dim(N)<\dim(M)$ and a smooth immersion $\Phi :N\rightarrow M$ such that $\Phi (N)=S$? I guess that the interior of $S$ has to be empty.

Furthermore: when is $N$ unique up to dipheomorphism?

It's a well known result that if $c$ is a regular value then $S$ is a closed embedded submanifold. So, in that line of thinking, probably you need to put some conditions to $c$, but I don't know which ones.

Partial answers are also welcome.

Thanks in advance.

Let $M$ be a smooth manifold and $f\in C^\infty(M)$. Let $S:=f^{-1}(\{c\})$ for some $c\in \operatorname{Im}(f)\subseteq\mathbb{R}$. When does exist a manifold $N$ with $\dim(N)<\dim(M)$ and a smooth immersion $\Phi :N\rightarrow M$ such that $\Phi (N)=S$? I guess that the interior of $S$ has to be empty.

Furthermore: when is $N$ unique up to dipheomorphism?

It's a well known result that if $c$ is a regular value then $S$ is a closed embedded hypersurface, so, in that line of thinking, probably you need to put some conditions to $c$, but I don't know which ones.

Partial answers are also welcome.

Thanks in advance.

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Let $M$ be a smooth manifold and $f\in C^\infty(M)$. Let $S:=f^{-1}(\{c\})$ for some $c\in \operatorname{Im}(f)\subseteq\mathbb{R}$. When does exist a manifold $N$ with $\dim(N)<\dim(M)$ and a smooth immersion $\Phi :N\rightarrow M$ such that $\Phi (N)=S$? I guess that the interior of $S$ has to be empty.

Furthermore: when is $N$ unique up to dipheomorphism?

It's a well known result that if $c$ is a regular value then $S$ is a closed embedded submanifold, but I'm asking for the next level of generality. So, in that line of thinking, probably you need to put some conditions to $c$, but I don't know which ones.

Partial answers are also welcome.

Thanks in advance.

Let $M$ be a smooth manifold and $f\in C^\infty(M)$. Let $S:=f^{-1}(\{c\})$ for some $c\in \operatorname{Im}(f)\subseteq\mathbb{R}$. When does exist a manifold $N$ with $\dim(N)<\dim(M)$ and a smooth immersion $\Phi :N\rightarrow M$ such that $\Phi (N)=S$? I guess that the interior of $S$ has to be empty.

Furthermore: when is $N$ unique up to dipheomorphism?

It's a well known result that if $c$ is a regular value then $S$ is a closed embedded submanifold, but I'm asking for the next level of generality. So, in that line of thinking, probably you need to put some conditions to $c$, but I don't know which ones.

Partial answers are also welcome.

Thanks in advance.

Let $M$ be a smooth manifold and $f\in C^\infty(M)$. Let $S:=f^{-1}(\{c\})$ for some $c\in \operatorname{Im}(f)\subseteq\mathbb{R}$. When does exist a manifold $N$ with $\dim(N)<\dim(M)$ and a smooth immersion $\Phi :N\rightarrow M$ such that $\Phi (N)=S$? I guess that the interior of $S$ has to be empty.

Furthermore: when is $N$ unique up to dipheomorphism?

It's a well known result that if $c$ is a regular value then $S$ is a closed embedded submanifold. So, in that line of thinking, probably you need to put some conditions to $c$, but I don't know which ones.

Partial answers are also welcome.

Thanks in advance.

Minor Math Jaxing
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Daniele Tampieri
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Let $M$ be a smooth manifold and $f\in C^\infty(M)$. Let $S:=f^{-1}(\{c\})$ for some $c\in Im(f)\subseteq\mathbb{R}$$c\in \operatorname{Im}(f)\subseteq\mathbb{R}$. When does exist a manifold $N$ with $dim(N)<dim(M)$$\dim(N)<\dim(M)$ and a smooth immersion $\Phi :N\rightarrow M$ such that $\Phi (N)=S$? I guess that the interior of $S$ has to be empty.

Furthermore: when is $N$ unique up to dipheomorphism?

It's a well known result that if $c$ is a regular value then $S$ is a closed embedded submanifold, but I'm asking for the next level of generality. So, in that line of thinking, probably you need to put some conditions to $c$, but I don't know which ones.

Partial answers are also welcome.

Thanks in advance.

Let $M$ be a smooth manifold and $f\in C^\infty(M)$. Let $S:=f^{-1}(\{c\})$ for some $c\in Im(f)\subseteq\mathbb{R}$. When does exist a manifold $N$ with $dim(N)<dim(M)$ and a smooth immersion $\Phi :N\rightarrow M$ such that $\Phi (N)=S$? I guess that the interior of $S$ has to be empty.

Furthermore: when is $N$ unique up to dipheomorphism?

It's a well known result that if $c$ is a regular value then $S$ is a closed embedded submanifold, but I'm asking for the next level of generality. So, in that line of thinking, probably you need to put some conditions to $c$, but I don't know which ones.

Partial answers are also welcome.

Thanks in advance.

Let $M$ be a smooth manifold and $f\in C^\infty(M)$. Let $S:=f^{-1}(\{c\})$ for some $c\in \operatorname{Im}(f)\subseteq\mathbb{R}$. When does exist a manifold $N$ with $\dim(N)<\dim(M)$ and a smooth immersion $\Phi :N\rightarrow M$ such that $\Phi (N)=S$? I guess that the interior of $S$ has to be empty.

Furthermore: when is $N$ unique up to dipheomorphism?

It's a well known result that if $c$ is a regular value then $S$ is a closed embedded submanifold, but I'm asking for the next level of generality. So, in that line of thinking, probably you need to put some conditions to $c$, but I don't know which ones.

Partial answers are also welcome.

Thanks in advance.

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