Timeline for Lifting a morphism along quotient of a group action
Current License: CC BY-SA 4.0
6 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Aug 29, 2022 at 5:43 | history | edited | user127776 | CC BY-SA 4.0 |
added 164 characters in body
|
Aug 29, 2022 at 5:39 | comment | added | user127776 | @KhashF BTW I am not sure if that example contradicted anything since the $U$ mentioned above is an etale open not a Zariski open. Meaning if we consider etale covers it should be possible to make your map from $X$ to $\mathbb{CP}^1$ liftable. I think my mentioning of Zariski or analytical open has confused many people, I should remove that. What I meant, is that there are two types of topologies on the hom space which comes from the Hilbert scheme one is Zariski and the other one is analytic. | |
Aug 28, 2022 at 20:43 | history | edited | user127776 | CC BY-SA 4.0 |
added 172 characters in body
|
Aug 28, 2022 at 20:37 | comment | added | user127776 | @KhashF Thanks, yes this is not true in general I should add what $Y$ and $G$ are supposed to be. | |
Aug 28, 2022 at 20:28 | comment | added | KhashF | What if we take $X$ and $Y$ to be compact Riemann surfaces with $g(X)<g(Y)$, and $Y$ admitting a Galois ramified cover $Y\rightarrow Y/G=\Bbb{CP}^1$? By the Riemann Existence Theorem, there exists a non-constant morphism $X\rightarrow \Bbb{CP}^1$, but there is no non-constant morphism from a non-empty Zariski open subset of $X$ to $Y$ since such a thing can be extended to a non-constant morphism $X\rightarrow Y$. | |
Aug 26, 2022 at 19:10 | history | asked | user127776 | CC BY-SA 4.0 |