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4 events
when toggle format what by license comment
Aug 22, 2022 at 17:40 comment added Thomas Dybdahl Ahle Does something like this work: $f_{n,k}$ is something like the gradient of the $s_{n+1,k+1}$, (you changed it to have falling $n$, but this seems to be an unimportant change from the original question.) By the Jacobian Conjecture $f$ is bijective if the determinant of the jacobian is a non-zero constant. The Jacobian of $f$ is the Hessian of $s$, and "... something about strict convexity implying the determinant being non-zero".
Aug 22, 2022 at 14:47 history edited Ewan Delanoy CC BY-SA 4.0
edited title
Aug 21, 2022 at 19:09 comment added LSpice I am not sure if it is a typo or intentional, but I think that 'tuple' is more common in English than 'uple' (although I have seen the construction "$n$-uple", usually in contexts more CS-y than maths-y).
Aug 21, 2022 at 17:28 history asked Ewan Delanoy CC BY-SA 4.0