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Nov 5 at 0:08 comment added Wlod AA The above def. of polymod is written unclearly. It'd be nice to include the (clear!) definition at the end of the question.
Jun 25, 2013 at 3:02 review Late answers
Jun 26, 2013 at 21:42
Oct 23, 2010 at 15:22 comment added Anonymous $\mathrm{polymod}$ is "polynomial mod". Two polynomials are congruent $\mathrm{polymod} p$ iff the coefficients each power of the variable are congruent $\pmod{p}$. The equivalence classes are sets of polynomials where each coefficient ranges over an equivalence class $\pmod{p}$. For the cousin, there are many local/globals but they all seem to require additional conditions (q.v. Hensel lifting). I think the set from which $x$ was chosen was left unspecified because this "imprecise mental abbreviation" pops up at various levels of sophistication each with a different such set.
Oct 20, 2010 at 18:40 comment added zhoraster Consequently, there are only $4$ polynomials over $\mathbb F_2$ Isn't this convenient? :-)
Oct 20, 2010 at 18:33 comment added zhoraster Probably I understand what this means: if $f(x)=0\pmod 2$ for all $x$, then $f=0$ over $\mathbb F_2$. This is similar to my second example: mathoverflow.net/questions/23478/…
Oct 20, 2010 at 18:25 comment added Mariano Suárez-Álvarez Either the cousin needs a bit more detail if it is to be false, it is quite naive!
Oct 20, 2010 at 11:47 comment added darij grinberg What does polymod mean?
Oct 20, 2010 at 4:02 history answered Anonymous CC BY-SA 2.5