Skip to main content
LaTeX
Source Link
Andrey Rekalo
  • 22.3k
  • 12
  • 89
  • 122

This is a common error made by mature mathematicians in many books and papers in analysis, especially in differential equations: If X$X$ is a closed subspace of a Banach space Y$Y$, then the Y^* $Y^*$ (the dual of Y$Y$) is isomorphic to a subspace of X^*$X^*$ (the dual of X$X$). It is false (of course) since Euclidian space R$\mathbb R$ is a subspace of R^2$\mathbb R^2$, yet the dual of R^2=R^2$\mathbb R^2=\mathbb R^2$ is not isomorphic to a subspace of the dual of R=R$\mathbb R=\mathbb R$. I guess, sometimes they really, really want it to be true. Cheers Boris

This is a common error made by mature mathematicians in many books and papers in analysis, especially in differential equations: If X is a closed subspace of a Banach space Y, then the Y^* (the dual of Y) is isomorphic to a subspace of X^* (the dual of X). It is false (of course) since Euclidian space R is a subspace of R^2, yet the dual of R^2=R^2 is not isomorphic to a subspace of the dual of R=R. I guess, sometimes they really, really want it to be true. Cheers Boris

This is a common error made by mature mathematicians in many books and papers in analysis, especially in differential equations: If $X$ is a closed subspace of a Banach space $Y$, then the $Y^*$ (the dual of $Y$) is isomorphic to a subspace of $X^*$ (the dual of $X$). It is false (of course) since Euclidian space $\mathbb R$ is a subspace of $\mathbb R^2$, yet the dual of $\mathbb R^2=\mathbb R^2$ is not isomorphic to a subspace of the dual of $\mathbb R=\mathbb R$. I guess, sometimes they really, really want it to be true. Cheers Boris

Post Made Community Wiki
Source Link

This is a common error made by mature mathematicians in many books and papers in analysis, especially in differential equations: If X is a closed subspace of a Banach space Y, then the Y^* (the dual of Y) is isomorphic to a subspace of X^* (the dual of X). It is false (of course) since Euclidian space R is a subspace of R^2, yet the dual of R^2=R^2 is not isomorphic to a subspace of the dual of R=R. I guess, sometimes they really, really want it to be true. Cheers Boris