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Aug 18, 2022 at 1:34 answer added user488927 timeline score: 4
Aug 17, 2022 at 9:13 comment added Franz Lemmermeyer As it stands, $I_K'$ is not a group.
Aug 17, 2022 at 6:15 comment added David Loeffler I'm guessing $P_K'$ is the principal ideals in $I_K'$, so this group (let's call it $Cl_K'$) is just the subgroup of $Cl_K$ generated by $P_K'$. So it does seem there is a genuine question here, namely "is it possible to make the choices of primes so that $Cl_K'$ is strictly smaller than $Cl_K$?". I would strongly suspect not, but I don't immediately see a proof.
Aug 16, 2022 at 13:22 history edited YCor CC BY-SA 4.0
removed capitals
Aug 16, 2022 at 11:57 comment added KConrad You did not define $P_K’$. And what do you mean by asking what a group “would be”? Even for the usual ideal class group, how would you answer the question “what is it”?
Aug 16, 2022 at 11:49 history asked user13953 CC BY-SA 4.0