Timeline for How many ways to flatten a Tesseract onto a table?
Current License: CC BY-SA 4.0
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S Aug 29, 2022 at 18:04 | history | bounty ended | CommunityBot | ||
S Aug 29, 2022 at 18:04 | history | notice removed | CommunityBot | ||
Aug 27, 2022 at 23:49 | comment | added | Ash | While 4-d to 2-d has been what most have attempted so far, I think going to 3-d first will make the attempt easier, & more human readable. I believe there is a 3-d polyhedron who's net will relate near directly to the tesseract's net. Currently studying the deltoidal icositetrahedron; I think taking it's net and treating 16 edges as higher dimensional will reveal some interesting things -- or at least I hope. Really excited for any answer to your question! | |
S Aug 21, 2022 at 17:00 | history | bounty started | ryu576 | ||
S Aug 21, 2022 at 17:00 | history | notice added | ryu576 | Draw attention | |
Aug 16, 2022 at 6:36 | comment | added | ryu576 | Reading through the paper, but I found it easier to go from 4-d to 2-d than going from 4-d to 3-d to 2-d. This is because in the 3-d version, you have to keep track of which faces are repeated and this becomes an additional headache. | |
Aug 15, 2022 at 11:44 | comment | added | Joseph O'Rourke | This will not help in the bounds, but one route is to first unfold to $\mathbb{R}^3$ and then unfold to $\mathbb{R}^2$ (rather than directly from 4D to 2D). This was used in Diaz, Giovanna, and Joseph O'Rourke. "Hypercube Unfoldings that Tile R^3 and R^2." arXiv:1512.02086 (2015). | |
Aug 15, 2022 at 7:10 | history | edited | ryu576 | CC BY-SA 4.0 |
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Aug 14, 2022 at 23:33 | history | edited | ryu576 | CC BY-SA 4.0 |
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Aug 14, 2022 at 21:16 | history | asked | ryu576 | CC BY-SA 4.0 |