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Jun 11, 2023 at 16:54 history edited LSpice CC BY-SA 4.0
TeX, while this is on the front page
Aug 13, 2022 at 20:46 vote accept IMeasy
Aug 13, 2022 at 16:04 comment added IMeasy I have edited the question to make a better link with the answers.
Aug 13, 2022 at 16:02 history edited IMeasy CC BY-SA 4.0
deleted 33 characters in body; edited title
Aug 13, 2022 at 0:08 answer added Theo Johnson-Freyd timeline score: 8
Aug 12, 2022 at 17:27 comment added Sam Hopkins A construction of the E8 root system is described here: en.wikipedia.org/wiki/E8_(mathematics)#E8_root_system
Aug 12, 2022 at 14:21 comment added abx The positive roots correspond to vectors with $q=1$ for the induced quadratic form. This is described for instance in Exercise 1 of Bourbaki Lie groups and Lie algebras, ch. VI, §4.
Aug 12, 2022 at 14:07 comment added IMeasy Yes, you are right, I am quite confused. The reduction modulo 2 of $E_8$ must have a quadratic form with values in $\mathbb{F}_2$ hence there is a non trivial map from $W(E_8)$ to the orthogonal group $O^+(8,\mathbb{F}_2)$ (with kernel $\pm 1$). So what is the relation with $\mathbb{F}_2^8$?
Aug 12, 2022 at 13:55 comment added abx I don't understand: $E_8$ has 120 positive roots, but $2^8-1=255$.
Aug 12, 2022 at 13:42 history asked IMeasy CC BY-SA 4.0